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CGP EDU Academic Team
Published on: August 14, 2026
The locus of the centre of a circle which touches externally the circle x 2 + y 2 – 6x – 6y + 14 = 0 and also touches the y-axis is given by the equation -
Text Solution
Verified by ExpertsThe correct answer is:
D
x 2 + y 2 – 6x – 6y + 14 = 0 ...(1)
⇒ C 1 (3, 3) , r 1 = 2
Locus of centre C 2 (h, k) = ?
C 2 N = r 2 = |h| ⇒ C 1 C 2 = (r 1 + r 2 )
Both the circles touches each other externally.
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