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CGP EDU Academic Team
Published on: August 14, 2026
The number of points on the line 3x + 4y = 5, which are at a distance of sec 2 θ + 2 cosec 2 θ , θ∈ R, from the point (1, 3), is-
Text Solution
Verified by ExpertsThe correct answer is:
B
The perpendicular distance of (1, 3) from the line 3x + 4y = 5 is 2 units while,
sec 2 θ + 2 cosec 2 θ ≥ 3 {as sec 2 θ , cosec 2 θ ≥ 1}
Evidently, these will be two such points on the line.
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