If sin ( α + β ) sin ( α – β ) = sin γ (2 sin β + sin γ ), 0 < α , β , γ < π, then the family of lines sin α x + sin β y + sin γ = 0 passes through
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sin ( α + β ) sin ( α – β ) = sin γ (2 sin β + sin γ )
(2 sin β + sin γ )
⇒ sin 2 α – sin 2 β = 2 sin β sin γ + sin 2 γ
⇒ sin 2 α – (sin β + sin γ ) 2 = 0
⇒ (sin α – sin β – sin γ ) (sin α + sin β + sin γ ) = 0
Since, 0 < α, β, γ < π
So, sin α + sin β , sin γ > 0
sin α + sin β + sin γ ≠ 0
So, sin α – sin β – sin γ = 0
or, (–1) sin α + 1 . sin β + sin γ = 0
Hence x sin α + y sin β + sin γ = 0
passes through (–1, 1).
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