Published by:
CGP EDU Academic Team
Published on: August 11, 2026
A straight line L with negative slope passes through the points (8, 2) and cuts the positive coordinate axes at points P and Q. As L varies the absolute minimum value of OP + OQ is
(O is origin)–
Text Solution
Verified by ExpertsThe correct answer is:
C
Let the equation of the line L be
y – 2 = m (x – 8), m < 0
coordinates of P and Q are P 
and Q (0, 2 – 8m)
So OP + OQ = 
+ 2 – 8m
= 10 + 
+ 8(–m)
≥ 10 + 2 
≥ 18
absolute min. value of OP + OQ = 18.
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