Published by:
CGP EDU Academic Team
Published on: August 12, 2026
A right-angled isosceles triangle right-angled at origin has 2x + 3y = 6 as its base. Area of the triangle, is-
Text Solution
Verified by ExpertsThe correct answer is:
B
Let OAB be the right-angled isosceles triangle.
Let ∠ AOX = θ , Then
∠ BOY = θ (see fig.).

Let OA = OB = r. Then, we have
A ≡ (r cos θ , r sin θ ) and B ≡ (–r sin θ , r cos θ )
Since A and B both lie on the given line 2x + 3y = 6, therefore we have
2 cos θ + 3 sin θ =
… (1)
and –2 sin θ + 3 cos θ =
… (2)
squaring and adding equations (1) and (2), we have
2 2 + 3 2 = 
given r 2 = 
Hence, area of Δ OAB, is
= 36/13.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The vertex of an equilateral triangle is (2, –1) and the equation of its base is . The length of i…
The area enclosed within the curve is
The area of the rhombus enclosed by the lines ax ± by ± c = 0 is
If the coordinates of the vertices of the triangle ABC be (–1, 6), (–3, –9) and (5, –8) respectivel…
In an isosceles triangle ABC , the coordinates of the point B and C on the base BC are respectively…
A square of side a lies above the x -axis and has one vertex at the origin. The side passing throug…