Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If the points 
, 
, where a, b, c are different from 1, lie on the line l x + my + n
= 0, then
A
a + b + c = – 
B
ab + bc + ca = 
C
abc = 
D
abc – (bc + ca + ab) + 3 (a + b + c ) = 0
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, d)
Since the given points lie on the line l x + my + n = 0, a, b, c are the roots of the equation
l 
+ m 
+ n = 0
or l t 3 + mt 2 + nt – (3m + n ) = 0 ... (i)
⇒ a + b + c = – 
; ab + bc + ca = 
... (ii)
and abc = 
... (iii)
So, that from (i), (ii) and (iii) we get abc – (bc + ca + ab) + 3 (a + b + c) = 0
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