Maths Differentiation and Applications of Derivatives Application in Mechanics and Rate Measurer Single Correct MCQ
Published on: August 13, 2026

The equations of motion of two stones thrown vertically upwards simultaneously are and respectively and the maximum height attained by the first one is h . When the height of the first stone is maximum, the height of the second stone will be

A
h /3
B
2 h
C
h
D
0

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The correct answer is:
D

The time taken by first stone to secure maximum height = .

The time taken by second stone to secure maximum height is, 1 sec . Therefore, in 2 sec , second stone will come back to the ground. Hence height .

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