Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Through the point P( α, β ) where αβ > 0, the straight line 
= 1 is drawn so as to form with axes a triangle of area
S. If ab> 0 then least value of S is
Text Solution
Verified by ExpertsThe correct answer is:
B
Area of Δ OAB = S = 
ab …….(i)
equation of AB is 
= 1
put ( α, β )
= 1
⇒ 
[using (i)]
⇒ a 2 β – 2aS + 2 α S = 0
∴ a ∈ R
⇒ D ≥ 0
4S 2 – 8 αβ S ≥ 0
S ≥ 2 αβ
Least value of S = 2 αβ
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