Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The area of a triangle formed by a line with co-coordinate axes is 54 
square units and the perpendicular drawn from the origin to the line makes an angle of 60º with the x-axis, find the equation of line.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. Let the equation of the line
x cos α + y sin α = p given α = 60º
∴ x cos 60º + y sin 60º = p
⇒ x + 
= 2p …(1)
intercept on x – axis ⇒ x = 2p ( y = 0) , intercept on y – axis ⇒ y = 2p/ 
( x = 0)
Given Area of Δ OAB = 54 
⇒ 1/2 (2p) (2p/ 
) =
54 
⇒ p = ± 9
∴ Equation of line x + 
= ± 18
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