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CGP EDU Academic Team
Published on: August 12, 2026
In a triangle ABC, cotA + cotB + cotC = cot θ .
( i) The possible value of θ is-
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CHECK THE SOLUTION.
(i)
cot 2 θ = 
[6 + (cotA – cotB) 2 + (cotB – cotC) 2 + (cotC – cotA) 2 ]
∴ cot 2 θ ≥ 3 ⇒ θ ≤ 30º.
(ii)
= 
= 
= 
= tan θ .
(iii)
cotB + cotC = cot θ – cotA
⇒ 
= 
⇒ Π (sinA – θ ) = sin 3 θ .
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