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CGP EDU Academic Team
Published on: August 14, 2026
If the roots of the equation x 2 – 2ax + a 2 + a – 3 = 0 are real less than 3, then
Text Solution
Verified by ExpertsThe correct answer is:
A
s
f (x) = x 2 – 2ax + a 2 + a – 3 = 0, f (3) > 0, α α + β β < 6, Δ Δ ≥ 0.
⇒ ⇒ a 2 – 5a + 6 > 0, a < 3, - 4a + 12 > 0 ⇒ ⇒ a < 2 or a > 3, a < 3,
a < 3 ⇒ ⇒ a < 2
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