Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If in a right angled triangle ABC, 4 sinAcosB – 1 = 0 and tanA is real then A,B,C are in-
Text Solution
Verified by ExpertsThe correct answer is:
A
Since 4sinA cosB = 1, so A and B cannot be 90 0
(as if B = 90 0 , then cosB = 0 and if A = 90 0 , tanA is not
defined)
∴ C = 90 0
B = 90 0 – A ⇒ 4sinAcos(90 0 – A) = 1
sin 2 A = 
⇒ sinA = 
⇒ A = 
⇒ B = 
So angle 
, 
, 
are in A.P
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