The centre of the required circle is the image of the centre with respect to the line mirror and radius is equal to the radius of the given circle.

Let ( h , k ) be the image of the point with respect to the line mirror. Then the mid-point of the line joining and lies on the line mirror.

or ….(i)

Also CP is perpendicular to

or ….(ii)

Solving (i) and (ii), .

Thus the centre of the image circle is . The radius of the image circle is same as the radius of i.e., 5.

Hence the equation of the required circle is

i.e. .