Published by:
CGP EDU Academic Team
Published on: August 12, 2026
The equation of the hyperbola whose directrix is
, focus (1, 1) and eccentricity
, is
Text Solution
Verified by ExpertsThe correct answer is:
A
, directrix is
and
. Now let the various point be
, then accordingly 
Squaring both the sides, we get

On simplification, the required locus is
.
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