Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The sum of three consecutive terms in a geometric progression is 14. If 1 is added to the first and the second terms and 1 is subtracted from the third, the resulting new terms are in arithmetic progression. Then the lowest of the original term is
Text Solution
Verified by ExpertsThe correct answer is:
B
Let the numbers be 
…..(i)
and 
….. (ii)
Put the value of a from (i) to (ii),
⇒ ⇒ 
⇒ ⇒ 
Numbers are 2, 4, 8 or 8, 4, 2. So lowest term in series is 2.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
For 0 < θ θ < π π /2, if x =
then
If a, b and c are distinct positive real numbers and a 2 +b 2 +c 2 =1, then ab + bc +ca is
If the product of n positive numbers is unity , then their sum is
If a, b and c are positive real numbers, then the least value of (a + b + c) is
If a, b and c are positive real numbers then is greater than or equal to
If the first and the (2n-1)th terms of an A.P., G.P. and H.P. are equal and their nth terms are a, …