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CGP EDU Academic Team
Published on: August 12, 2026
Equation of a circle with centre (4, 3) touching the circle x 2 + y 2 = 1 is
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Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(c, d)
Let the circle touching the circle x 2 +y 2 = 1,
be x 2 +y 2 -8x-6y+k = 0.
The equation of the common tangent is
S 1 – S 2 = 0 i.e. 8x + 6y-1-k = 0.
This is a tangent to the circle x 2 +y 2 = 1.
Hence ± ± 1 = 
⇒ ⇒ k+1 = ± ± 10
⇒ ⇒ k = -11 or 9.
Therefore the circles are x 2 +y 2 -8x-6y+9 = 0 and
x 2 +y 2 -8x-6y-11 = 0
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