Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Equation of a circle with centre C(h, k) such that h 2 –3h + 2 = 0 and k 2 –5k + 6 = 0 having radius 4 is
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, b, c, d)
h 2 –3h + 2 = 0 ⇒ h = 1, 2
k 2 –5k + 6 = 0 ⇒ k = 2, 3
∴ (h, k) ≡ (1, 2), (1, 3), (2, 2) or (2, 3)
∴ Circles, centered at (h, k) and radius = 4, are given by
(x – 1) 2 + (y – 2) 2 = 16, (x – 1) 2 + (y – 3) 2 = 16
(x – 2) 2 + (y – 2) 2 = 16, (x – 2) 2 + (y – 3) 2 = 16
∴ , , and are correct.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A point P moves in such a way that the ratio of its distances from two coplanar points is always fi…
The equation of a circle with origin as centre passing through the vertices of an equilateral trian…
If the line is a diameter of the circle then b =
The centre of the circle is
Let be the equation of a circle. If has equal roots and has roots then the centre of the circl…
If the lines and are tangents to a circle, then the radius of the circle is