Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The least distance of the point (3, 2) from the parabola y = x 2 + 2 is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
Let P(x, x 2 +2) be the nearest point of Q(3, 2) on the given parabola. Then
PQ 2 = (x – 3) 2 + x 4 (PQ
2 ) 1 = 2(x – 3) + 4x 3 = 0 ⇒ ⇒ x = 1
also (PQ 2 ) 11 > 0 when x = 1
∴ ∴ The nearest point of Q(3, 2) is P(1, 3)
∴ ∴ Shortest distance = PQ = 
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