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CGP EDU Academic Team
Published on: August 14, 2026
The abcissa and ordinate of the end points A and B of a focal chord of the parabola y 2 = 4x are respectively the roots of x 2 – 3x + a = 0 and y 2 + 6y + b = 0. The equation of the circle with AB as diameter is.
Text Solution
Verified by ExpertsThe correct answer is:
B
t 1 t 2 = – 1 as AB is focal chord
x 2 – 3x + a = 0 ; x 1 + x 2 = 3 & x 1 x 2 = a
y 2 + 6y + b = 0 ; y 1 + y 2 = – 6 & y 1 y 2 = b
x 1 x 2 = 
. t 1 2 = 1 = a
y 1 y 2 = 2t 1 
= – 4 = b
a = 1, b = – 4
equation of circle AB is diameter
x 2 + y 2 – 3x + 6y – 3 = 0
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