Home Maths Conic Sections Parabola A movable parabola touches the x and the y-a…
Maths Conic Sections Parabola Single Correct MCQ
Published on: August 13, 2026

A movable parabola touches the x and the y-axes at (1, 0) and (0, 1). Then the locus of the focus of the parabola is-

A
2x 2 – 2x + 2y 2 – 2y + 1 = 0
B
x 2 – 2x + 2y 2 – 2y + 1 = 0
C
2x 2 – 2x + 2y 2 + 2y + 2 = 0
D
2x 2 + 2x – 2y 2 – 2y – 2 = 0

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Text Solution

Verified by Experts
The correct answer is:
A

Since the x-axis and the y-axis are two perpendicular tangents to the parabola and both meet at the origin, the directix passes through the origin.

Let y = mx be the direction and (h, k) be the focus.

FA = AM

= … (1)

and FB = BN

= … (2)

From equation (1) and (2), we get

(h – 1) 2 + h 2 + k 2 + (k – 1) 2 = 1

⇒ 2x 2 – 2x + 2y 2 – 2y + 1 = 0 is the required locus.

Hence is correct answer.

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