Published by:
CGP EDU Academic Team
Published on: August 12, 2026
The eccentricity of the hyperbola conjugate ot x 2 – 3y 2 = 2x + 8 is
A
B
C
2
D
None of these
Text Solution
Verified by ExpertsThe correct answer is:
C
Given, equation of hyperbola is x 2 – 3y 2 = 2x + 8
⇒ ⇒ x 2 – 2x – 3y 2 = 8
⇒ ⇒ (x – 1) 2 – 3y 2 = 9
⇒ ⇒ 
= 1
Conjugate of this hyperbola is = 
= 1
And its eccentricity (e) = 
Here, a 2 = 9, b 2 = 3; ∴ ∴ e = 
= 2.
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