The points of intersection of the curves whose parametric e…

Maths Conic Sections Conic Section - General Single Correct MCQ

Published on: August 13, 2026

The points of intersection of the curves whose parametric equations are x = t 2 + 1, y = 2t and x = 2s, y = 2/s is given by

(1, -3)

(2, 2)

(-2, 4)

(1, 2)

Text Solution

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The correct answer is:

Eliminating t from x = t 2 + 1, y = 2t, we obtain y 2 = 4x - 4. Substituting x = 2s, y = in y 2 = 4x - 4, we obtain

2s 3 - s 2 - 1 = 0 ⇒ ⇒ (s - 1) (2s 2 + s + 1) = 0 ⇒ ⇒ s = 1

Putting s = 1 in x = 2s, y = 2/s, we obtain x = 2, y = 2.

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