Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Let y 2 = 4ax be parabola and PQ be a focal chord of parabola. Let T be the point of intersection of tangents at P and Q. Then
A
Area of circumcircle of Δ PQT is 
B
Orthocenter of Δ PQT will lie on tangent at vertex.
C
Incenter of Δ PQT will be vertex of parabola.
D
Incentre of Δ PQT will lie on directrix of parabola.
Text Solution
Verified by ExpertsThe correct answer is:
A
for focal chord t 1 t 2 = – 1
Tangent drawn at the extremities of focal chord are perpendicular and meet at directrix
∠ PTQ = 90 0
Hence PQ is diameter of circum circle of Δ PTQ.
2r = PQ ⇒ r = (PQ/2)
Area of circum circle π r 2 = 
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