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CGP EDU Academic Team
Published on: August 14, 2026
Tangent to the curve y = x 2 + 6 at a point P(1, 7) touches the circle x 2 + y 2 + 16x + 12y + c = 0 at a point Q. Then the coordinate of Q are-
Text Solution
Verified by ExpertsThe correct answer is:
D
Equation of tangent at P to the parabola
2y = 2x 2 + 6 × 2
y + 7 = 2x . 1 + 12
2x – y + 5 = 0 …(1)
Equation of normal at Q
x + 2y + λ = 0
– 8 – 12 + λ = 0 ⇒ λ = 20
x + 2y + 20 = 0 …(2)
Solving (1) and (2)
x = – 6, y = – 7
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