Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Let 'd' be the perpendicular distance from the centre of the ellipse 
+ 
= 1 to the tangent drawn at a point P on the ellipse. If F 1 and F 2 are the two foci of the ellipse then
(PF 1 – PF 2 ) 2 = K 
where K=
Text Solution
Verified by ExpertsThe correct answer is:
A
Let tangent is x = a and P(a, 0)
Now, PF 1 = a – ae, PF 2 = a + ae ⇒ d = a
= (PF 1 – PF 2 ) 2 ⇒ (a – ae – (a + ae)) 2 = 4a 2 e 2 = 4a
2 
= 4a 2 
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