Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Let PQ be a double ordinate of hyperbola 
= 1. If O be the centre of the hyperbola and OPQ is an equilateral triangle then the eccentricity e is -
A
> 
B
> 2
C
> 2/ 
D
None of these
Text Solution
Verified by ExpertsThe correct answer is:
C
P be ( α, β ) then PQ = 2 β
OP = 
Since OPQ is an equilateral triangle
OP = PQ
α 2 + β 2 = 4 β 2 = α 2 = 3 β 2 ⇒ α = ± 
β
( α, β ) is situated on the hyperbola
= 1 
= 1
= 1 ⇒ 
– 
= 
> 0
> 1/3 ⇒ e 2 – 1 > 1/3
e 2 > 4/3 ⇒ e > 2/ 
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