Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If foci of hyperbola lie on y = x and one of asymptote is y = 2x, then equation of hyperbola, given that it passes through (3, 4) is-
A
x 2 – y 2 – 
xy + 5 = 0
xy + 5 = 0
B
2x 2 – 2y 2 + 5xy + 5 = 0
C
2x 2 + 2y 2 + 
xy + 5 = 0
xy + 5 = 0
D
None of these
Text Solution
Verified by ExpertsThe correct answer is:
D
Major axis of hyperbola bisects asymptote
∴ equation of other asymptote is y = 
equation of hyperbola is (y –2x) (x –2y) + k = 0
put (3, 4)
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