Home Maths Differentiation and Applications of Derivatives General Locus of a point at which the circles x 2 + …
Maths Differentiation and Applications of Derivatives General Single Correct MCQ
Published on: August 13, 2026

Locus of a point at which the circles x 2 + y 2 –2x –2y –7 = 0 and x 2 + y 2 + 8x + 6y = 0 subtend equal angles, is -

A
The complete circle 16x 2 +16y 2 –122x–104y–175=0
B
A minor arc of the circle 16x 2 +16y 2 –122x–104y–175=0
C
A major arc of the circle 16x 2 +16y 2 –122x–104y–175 = 0
D
Exactly two points on the circle 16x 2 +16y 2 –122x – 104y –175 = 0

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Text Solution

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The correct answer is:
C

Two circles cut each other, also locus is obtained by 2tan –1 = 2 tan –1

which is 16x 2 + 16y 2 – 122 x – 104y – 175 = 0 whose centre lies outside smaller circle .

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