Consider two functions y = f(x) and y = g(x) defined as
f(x) = 
and
g(x) = 
(i) f(x) is continuous at x = 1 but not differentiable at x = 1, if
Text Solution
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Ans.
(i)
Sol. 

For continuity a + b = 4b i.e., a = 3b .....(i)
f(1 + ) = 
= 
=
= 2b
f(1 – ) = 
= 
=
= 2a
2a ≠ 2b, a ≠ b.
(ii)
Sol.
=
= 4c + d
=
= 2d + 3 – c
g(2) = 4c + d
∴ 4c + d = 2d + 3 – c
∴ d = 5c – 3.
(iii)
Sol.
, 
= 5a – 6
Since f(x) is continuous at x = 3
∴ 8b = 5a – 6 .....(i)
f ' (3 – ) = 
=
= 2b
f '(3 + ) = 
= 
Since f is differentiable at x = 3
∴ 5a – 8b – 6 = 0
∴ f '(3 + ) = a – 1
Thus, a – 1 = 2b .....(ii)
From Esq. (i) and (ii), we get
a = 2, b = 
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