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CGP EDU Academic Team
Published on: August 12, 2026
f(x) = x + x –1 , then
Text Solution
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CHECK THE SOLUTION.
(c, d)
f '(x) = 1–1/x 2
f '(x) = 0 ⇒ x = ± 1 and f "(x) = 2/x 3 , f "(1) > 0 & f "(–1) < 0
f(x) has maximum value f(–1) and the minimum value f(1)
f(–1) = – 1 –
= – 2
f(1) = 1 + 1/1 = 2
∴ max. f(x) < min. f(x)
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