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CGP EDU Academic Team
Published on: August 13, 2026
The tangent at any point P of a curve c meets the x axis at Q whose abscissa is positive and OP = OQ, O being the origin. Curve c passes through the point (1, 0) and tangent on point (1, 0) is given by x = a. Then a equals to...........
Text Solution
Verified by ExpertsThe correct answer is:
0001
Ans. 0001
Sol. (Y – y) = 
(X – x)
Thus meet x axis at 
OP = OQ 
= x – y 
– 
= dy
= 
dy
= – 
dy
log 
= – log y + log k
= k
passes through (1,0)
k = 2
x 2 + y 2 = (2 – x) 2
y 2 = 4 – 4x
y 2 = – 4(x – 1)
vertex (1, 0)
tangent at vertex
x = 1 ⇒ a = 1
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