Home Maths Differentiation and Applications of Derivatives General Point on y 2 = 4x that is nearest to the cir…
Maths Differentiation and Applications of Derivatives General Single Correct MCQ
Published on: August 13, 2026

Point on y 2 = 4x that is nearest to the circle x 2 + (y – 12) 2 = 1, is

A
(4, -4)
B
(4, 4)
C
(9, 6)
D
(9, -6)

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Text Solution

Verified by Experts
The correct answer is:
B

Shortest distance between two curves always occur along the common normal. That means if 'P' is the required point then PA becomes the common normal.

Let P ≡ ≡ (t 2 , 2t). Equation of normal at 'P' is :

y = − − tx + 2t + t 3 , it should pass through (0, 12). Thus t 3 + 2t − − 12 = 0

⇒ ⇒ t = 2. Hence P = (4, 4).

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