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CGP EDU Academic Team
Published on: August 14, 2026
If 2x 3 –3x 2 y 2 + 4x – y + 7 = 0 and y(1) = 1, then the value of y ′′ (1) is equal to-
Text Solution
Verified by ExpertsThe correct answer is:
B
(1) y (1) = 1 given
⇒ x = 1, y = 1
(2) diff. 6x 2 –6xy 2 – 6x 2 yy ′ + 4 – y ′ = 0
put x = 1; y = 1
6 – 6 – 6y ′ (1) + 4 – y ′ (1) = 0
⇒ y ′ (1) = 
(3) Differentiating 12x – 6y 2 –12 xyy ′′ – 6x 2 (y ′ ) 2 – 6x 2 yy ′′
= 0
Put x = 1 ; y = 1; y ′ (1) = 1
y ′′ (1) = – 
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