Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let ƒ : [2, 7] → [0, ∞ ) be a continuous and differentiable function. Then
(ƒ (7) – ƒ (2))
where c ∈ [2, 7]
Text Solution
Verified by ExpertsThe correct answer is:
A
Let g(x) = ƒ 3 (x)
⇒ g ′ (x) = 3ƒ 2 (x) . ƒ ′ (x)
ƒ : [2, 7] → [0, ∞ ) ⇒ g : [2, 7] → [0, ∞ )
Using Lagrage’s Mean Value theorem on g(x) we get
g ′ =
; c ∈ [2, 7]
⇒ 5 ƒ 2 ƒ ′ = (ƒ(7) – ƒ(2))
.
Hence is the correct answer.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If f(x) = cos π x + 10x + 3x 2 + x 3 , – 2 ≤ x ≤ 3 then absolute minimum value of f(x) is-
The function f(x) = x 5 – 5x 4 + 5x 3 – 1 has-
The function f(x) = has no extrema. if (n ∈ z)
If x exceeds by its square by the greatest possible quantity then x is-
An extreme value of the function
f(x) = (sin –1 x) 3 + (cos –1 x) 3 (–1 < x < 1) is
Let f(x) = (t + 4) 4 log (t+ 1) dt, then -