Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The minimum length of radius vector of the curve
= 1 is
Text Solution
Verified by ExpertsThe correct answer is:
B
= 1 (Let x = r cos φ , y = r sin φ )
r 2 = a 2 sec 2 φ + b 2 cosec 2 φ
Let r 2 = z, z = a 2 sec 2 φ + b 2 cosec 2 φ
= a 2 2 sec φ sec φ tan φ – b 2 2 cosec φ cosec φ cot φ = 0
a 2 sec 2 φ tan φ = b 2 cosec 2 φ cot φ
tan 4 φ = 
⇒ tan φ = 
or 
= a 2 
+ b 2 
= (a + b) 2
∴ r min = |a + b|
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