Locus of z such that Arg (z + i) – Arg (z – i) = π/2 is sem… | CGP Edu

Maths Complex Number Argument of Complex Number Subjective Type

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Published on: August 13, 2026

Locus of z such that Arg (z + i) – Arg (z – i) = π/2 is semicircle x 2 + y 2 = 1 in first and fourth quadrants.

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