Published by:
CGP EDU Academic Team
Published on: August 12, 2026
Prove that: log 2 <
dx < 
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. For all x ∈ [0, 1], we have
1–x 2 < 1 + x 6 < (1 + x) 2 ⇒
<
< 
⇒
<
< 
⇒
dx <
dx <
dx
⇒ [log (1+ x)
<
dx < [sin
–1 x 
⇒ log 2 <
dx < sin –1 1
⇒ log 2 <
dx < 
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