The differential equation of :
Column- I | Column- II |
(i) y = a sin (mx + b), a, b and m are parameter | [A] y3 = y1 |
(ii) y = ax2 + bx + c | [B] y3 = 0 |
(iii) y = Aex + Be–x + C | [C] y3y = y1y2 |
Text Solution
Verified by Experts(i) [C]; (ii) [B]; (iii) [A]
Ans.
(i) [C]
(ii) [B]
(iii) [A]
Sol. Differentiating twice w.r.t x the equation in
(i), y 1 = ma cos (mx + b), y 2 = –am 2 sin (mx + b) = –m 2 y
Differentiating again, we get y 3 = –m 2 y 1 = y 1
⇒ y 3 y= y 2 y 1
Differentiating twice equation in (iii) w. r. t. x, we get
y 1 = Ae x – Be –x , y 2 = Ae x + Be –x = y – c ⇒ y 3 = y 1
Differentiating thrice w.r.t. x the equation in (ii), we have
y 3 = 0
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