A bag contains 5 balls; 3 balls are drawn in succession
without replacement and two white and 1 black ball are
obtained. If it is known that every ball in the bag is either
white or black, then the probability that, the next draw will
give white ball.
Text Solution
Verified by ExpertsB
Let E 0 , E 1 , E 2 be the events that the bag contains 2,3,4 white balls.
P(E 0 ) = P(E 1 ) = P(E 2 ) = 1/3.
Let E be the event of drawing 2 white and 1 black balls.
P(E/E 0 ) = 
P(E/E 1 ) =
P(E/E 2 ) =
.
P(E 0 /E) = 
P(E 1 /E) = 2/5; P(E 2 /E) = 2/5.
Probability that next draw will give white ball = P(E 0 /E).0 + P(E 1 /E)
+ P(E 2 /E).1
= 0 +
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems