Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Let A be vector parallel to the line of intersection of planes P 1 and P 2 through origin. P 1 is parallel to the vectors 2j + 3k and 4j – 3k and P 2 is parallel to j – k and 3i + 3j, then the angle between A and 2i + j – 2k is -
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(b, d)
vector 
is parallel to
[(2j + 3k) × (4j – 3k)] × [(j – k) × (3i + 3j)] ⇒ 54 (j – k)
If θ is the required angle then cos θ = ± 
⇒ ± 
⇒ θ = π /4, 3 π /4
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