If 
and 
are two non zero, non-collinear vectors satisfying
((a - 3) 
2 + (b - 4) 
+ (c - 1)) 
+ [(a - 3) 
2 + (b - 4) 
+ (c - 1)] 
+ [(a - 3) 
2 + (b - 4) 
+ (c - 1)] 
(where 
are three distinct numbers), then the value of 
is equal to
Text Solution
Verified by ExpertsA
: 6.5
Since, 
and 
are 3 non-coplanar vectors
Hence, (a - 3) 
2 + (b - 4) 
+ (c - 1) = 0
(a - 3) 
2 + (b - 4) 
+ (c - 1) = 0
(a-3) 
2 + (b-4) 
+(c-1) = 0
We can say that (a - 3)x 2 + (b - 4)x + (c - 1) = 0 has roots 
Since, quadratic has 3 roots so it becomes an identity
a-3 = 0, b-4 = 0, c - 1 = 0
a = 3, 6 = 4, c = 1
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