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CGP EDU Academic Team
Published on: August 13, 2026
The equation of a plane containing the line formed by2x-y + z - 3 = 0, 3x + y + z = 5 and at a distance of 
units from the point (2,1, -1)is
Text Solution
Verified by ExpertsThe correct answer is:
D
62x + 29y + 19z - 105 = 0
Equation of the required plane is
(2x - y + z - 3) + 
(3x + y + z - 5) = 0
(2 + 3 
)x + ( 
- l)y + ( 
+ l)z - 3 - 5 
= 0
Distance of the plane from (2,1, -1) = 
Hence, the equation of the plane is
62x + 29y + 19z - 105 = 0
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