Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Consider the planes P 1 :2x -y + z = 6 and P 2 :x + 2y - z = 4 having normals
and
respectively. The distance of the origin from theplane passing through the point (1,1,1) and whose normal is perpendicular to N 1 and N 2 is
Text Solution
Verified by ExpertsThe correct answer is:
B
units
(given)
(given)
normal of required plane is 



So, equation of the required plane is

-x + 3y + 5z - 7 = 0
x-3y-5z + 7 = 0
So, distance from (0,0, 0) is = 

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