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CGP EDU Academic Team
Published on: August 13, 2026
Let P 1 :x - 2y + 3z = 5 and P 2 :2x - 3y + z + 4 = 0 be two planes. The equation of the plane perpendicular to the line of intersection of P 1 = 0 and P 2 = 0 and passing through (1,1,1) is
Text Solution
Verified by ExpertsThe correct answer is:
B
7z + 5y + z=13
The normal vector of plane P 1 = 0 is 
The normal vector of plane P 2 = 0 is 
A vector parallel to the line of intersection of P 1 =0 and P 2 = 0 is
It is also a normal vector for the required plane
Hence, the equation of the required plane is
7(x-1) + 5(y-1) + (z-1) = 0
7x + 5y + z-13 = 0
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