Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The angle of elevation of an object on a hill is observed from a certain point in the horizontal plane through its base, to be 30°. After walking 120 m towards it on a level ground, the angle of elevation is found to be 60°. Then the height of the object (in metres) is
A
120
B
60 
C
120 
D
60
Text Solution
Verified by ExpertsThe correct answer is:
B
60 
In 
CAD, tan 30° = 
...(i)
and in 
CBD, tan 60° = 
….(ii)
From Eqs. (i) and (ii), we get, x = 60 m
On putting x = 60 in Eq.(i), we get
h = 60 
m
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A tower subtends angles a, 2a and 3a, respectively, at points A, B and C all lying on a horizontal …
PQR is a triangular park with PQ = PR = 200m. A TV tower stands at the mid-point of QR. If the angl…
A harbour lies in the direction 60° south-west from a fort and at a distance of 30 km from it. A sh…
The angular depressions of the top and the foot of a tower, as seen from the top of a second tower …
A vertical tower subtends an angle of 60° at a point on the same level as the foot of the tower. On…
A flag - staff of 5 meters high stands on a building of 25 meters height. For an observer at a heig…