Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Suppose that the side lengths of a triangle are three consecutive integers and one of the angles is twice another. The number of such triangles is/are
Text Solution
Verified by ExpertsThe correct answer is:
A
1
Let B = 2 A and BD be the bisector of angle B, then
& 
Now, 
ABC and 
BDC are similar, so
…(i)
Since, b > a 
Either b = a+1 or b = a + 2, if b = a + 1, then [From Eq.(i)]
c is integer 
a=1,b = 2,c = 3 but then, no triangle will form.
If b = a + 2, then obviously c = a + 1, and then, [from Eq. (i)]
or a = 4
a = 4, b = 6, c = 5 is the only possible solution.
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