Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Find the equation of all possible normals to the curve x 2 = 4y drawn from the point (1,2)
(1, 2) x 2 = 4y
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Let point Q be 
and point P be the point of contact on the curve.
Now, m PQ = slope of the normal at Q.
Differentiating x 2 = 4y w.r.t we get 2x = 4 
or 
= 
or Slope of the normals at Q = 
or 
[From (1)]
or 
– 2h = – 2h + 2 or h 3 = 8 or h = 2
Hence, the coordinates of point Q are (2, 1) and so the equation of the required normal becomes
x + y = 3
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