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CGP EDU Academic Team
Published on: August 13, 2026
Let f(x) = (1 + b 2 )x 2 + 2bx + 1 and let m(b) be the minimum value of f(x). As b varies, the range of m(b) is
Text Solution
Verified by ExpertsThe correct answer is:
D
Since coefficient of x 2 is (+ve)
⇒ m(b) =
m(b) = –
⇒ m(b) = 
⇒
⇒ 1 + b 2 ≥ 1 ⇒
⇒ m(b) ∈ (0, 1]
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