Maths Differentiation and Applications of Derivatives General Single Correct MCQ
Published on: August 11, 2026

Column-I Column-II

A
The number of point (s) of maxima of f(x) = x 2 + is (p) 0
B
(sin – 1 x) 3 + (cos – 1 x) 3 is maximum at x = (q) 2
C
If [a, b], (b < 1) is largest interval in which (r) f(x) = 3x 4 + 8x 3 – 6x 2 – 24x + 19 is strictly increasing then is
D
If a + b = 8, a, b > 0 then minimum value of is (s) –1

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Text Solution

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The correct answer is:
CHECK THE SOLUTION.

f ′ (x) = 2x – =

No point of local maxima

Given expression = (sin – 1 x) 3 + (cos – 1 x) 3

= – 3sin – 1 x

= (sin –1 x) 2 – sin –1 x +

This is quadratic in sin –1 x. Therefore it will give maximum value when

sin –1 x = – ⇒ x = –1

f’(x) = 12 (x + 2)(x + 1) (x – 1)

⇒ a = – 2, b = – 1

= = (3a 2 – 24a + 64)

Minimum is =

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