Published by:
CGP EDU Academic Team
Published on: August 12, 2026
Let ABC is given triangle having respective sides a,b,c. D,E,F are points of the sides BC,CA,AB respectively so that AFDE is a parallelogram. The maximum area of the parallelogram is
A
bcsinA
B
bcsinA
C
bcsinA
D
bcsinA
Text Solution
Verified by ExpertsThe correct answer is:
A
From similar triangles Δ ABC, Δ FBD
= 
Area of AFDE = xy sin A
= 
(c – x) sin A
It is maximum when x = 
∴ Maximum area = 
sinA
statement -1 is true
statement-2 is obvious.
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